Edit report at http://bugs.php.net/bug.php?id=53059&edit=1

 ID:                 53059
 User updated by:    vixio_calm at yahoo dot com
 Reported by:        vixio_calm at yahoo dot com
 Summary:            When we put a numeric value in "Like" query, there
                     is no result
 Status:             Bogus
 Type:               Bug
 Package:            Scripting Engine problem
 Operating System:   Windows XP sp2
 PHP Version:        5.2.14
 Block user comment: N

 New Comment:

Oke ahar...@php.net,

Sorry for this inconvenience.

My problem is about a different database connection.

:lol, Sorry I didnt chek it before.

I found my problem yet.

Thnx for your attention.


Previous Comments:
------------------------------------------------------------------------
[2010-10-14 04:45:18] ahar...@php.net

Sorry, but your problem does not imply a bug in PHP itself.  For a
list of more appropriate places to ask for help using PHP, please
visit http://www.php.net/support.php as this bug system is not the
appropriate forum for asking support questions.  Due to the volume
of reports we can not explain in detail here why your report is not
a bug.  The support channels will be able to provide an explanation
for you.

Thank you for your interest in PHP.



------------------------------------------------------------------------
[2010-10-14 02:40:11] vixio_calm at yahoo dot com

Description:
------------
//I have a script like this, when I put '%1%', there is no result, even
in view_userstructure there are a data that use '1'.





Test script:
---------------
$query=mysql_query("SELECT * FROM view_userstructure WHERE SECTIONNAME
LIKE '%1%'")or die(mysql_error());

$row_number = mysql_num_rows($query);

Expected result:
----------------
I want to get a result like when I run that query in phpMyAdmin



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