Edit report at http://bugs.php.net/bug.php?id=54279&edit=1

 ID:                 54279
 Updated by:         fel...@php.net
 Reported by:        donciprian at gmail dot com
 Summary:            preg_grep does not recognize this regex '/[0-9]*$/'
                     to filter numbers out
-Status:             Open
+Status:             Bogus
 Type:               Bug
 Package:            PCRE related
 Operating System:   Ubuntu 10.10
 PHP Version:        5.3SVN-2011-03-16 (SVN)
 Block user comment: N
 Private report:     N

 New Comment:

Thank you for taking the time to write to us, but this is not
a bug. Please double-check the documentation available at
http://www.php.net/manual/ and the instructions on how to report
a bug at http://bugs.php.net/how-to-report.php

There is no bug here... preg_grep is not meant to return the group
captured data separately... You need to use
preg_match()/preg_match_all() for such.


Previous Comments:
------------------------------------------------------------------------
[2011-03-16 23:26:42] donciprian at gmail dot com

Description:
------------
I am trying to filter numbers from the end of a string in a array.



i have a array full of these strings :



$testArr = array('foto_1','foto_45');



$resArr = preg_grep('/[0-9]*$/',$testArr);



and the $resArr array that gets returned from preg_grep, contains the
same

strings, i am looking for a array that contains just the numbers that
were 

filtered using the regex





Test script:
---------------
<?php



$testArr = array('foto_1','foto_45');



$resArr = preg_grep('/[0-9]*$/',$testArr);



print_r($resArr);



?>

Expected result:
----------------
to see a array full of the numbers what were at the end of the string in
the 

input array



something like this :



Array

(

    [0] => 1

    [1] => 45

)

Actual result:
--------------
Array

(

    [0] => foto_1

    [1] => foto_45

)


------------------------------------------------------------------------



-- 
Edit this bug report at http://bugs.php.net/bug.php?id=54279&edit=1

Reply via email to