Edit report at https://bugs.php.net/bug.php?id=55266&edit=1

 ID:                 55266
 Comment by:         g...@php.net
 Reported by:        mchlpl at gmail dot com
 Summary:            Traits vs Type hints
 Status:             Open
 Type:               Feature/Change Request
 Package:            Class/Object related
 PHP Version:        5.4.0alpha2
 Block user comment: N
 Private report:     N

 New Comment:

My view on this issue is that traits do not constitute types and do not provide 
interfaces. (I proposed the later one in the beginning in the sense of traits 
are interfaces with implementation, but this was disregarded to make clear that 
traits are neither classes nor interfaces.)

Thus, is_a should also not say anything about a trait.
Traits are not units of encapsulation, they do not guarantee to provide/protect 
any invariants.

However, if you need to know what traits are used by a class, please refer to: 
ReflectionClass::getTraits()

I just noticed that we have the following function in the SPL:
http://php.net/manual/en/function.class-implements.php
That should probably be mirrored to provide the same functionality as 
ReflectionClass::getTraits().

Not sure what the design policies are here. From a symmetry perspective there 
should be a class_uses() function, but from my personal perspective, 
class_implements should get nuked and uses should transition to the reflection 
extension if they need such meta programming facilities. Well, the later is not 
practical, so we will probably need to have class_uses().


Previous Comments:
------------------------------------------------------------------------
[2011-07-22 14:51:09] alex dot howansky at gmail dot com

> $a is not an instance of the trait but rather of
> the class that utilizes the trait.

You can say the same of interfaces and abstracts, but is_a returns true for 
them.

Test script:
---------------
trait someTrait {}

interface someInterface {}

abstract class someAbstract {}

class someClass extends someAbstract implements someInterface {
    use someTrait;
}

$a = new someClass();
var_dump(is_a($a, 'someClass'));
var_dump(is_a($a, 'someAbstract'));
var_dump(is_a($a, 'someInterface'));
var_dump(is_a($a, 'someTrait'));

Expected result:
----------------
bool(true)
bool(true)
bool(true)
bool(?)

Actual result:
----------------
bool(true)
bool(true)
bool(true)
bool(false)

------------------------------------------------------------------------
[2011-07-22 14:50:36] mchlpl at gmail dot com

Mike: That's one way of looking at it. My point of view is that a trait adds 
methods to class' interface (where interface is a set of public members of a 
class - both methods and fields) and this should be reflected in class type.

Currently (unless I missed something that was not mentioned in RFC - I admit to 
not have gone through SVN version of docs) there seem to be no way to check if 
class uses a trait or no. Only new functions mentioned are trait_exists() and 
get_declared_traits(). Checking if the object has a method will not work, if 
trait is meant to override method in host class. Having traits reflected in 
object's type, would solve this problem nicely. Adding another function to 
glabal namespace (uses_trait() ?) is not something I would like to see.

------------------------------------------------------------------------
[2011-07-22 13:36:59] me at mikestowe dot com

I believe this is the correct result as $a is not an instance of the trait but 
rather of the class that utilizes the trait.

------------------------------------------------------------------------
[2011-07-22 07:44:34] mchlpl at gmail dot com

Description:
------------
Traits, when used in a class, are not added to class' type, and therefore can 
not be use in type hints. The RFCs on traits https://wiki.php.net/rfc/traits  
and on horizontal reuse https://wiki.php.net/rfc/horizontalreuse do not explain 
if this is by design.

On the other hand Traits seem to share the same namespace as Classes and 
Interfaces, since it is impossible to have an Interface and a Trait that share 
the name ('Fatal error: Cannot redeclare class' is raised when this is 
attempted).

Test script:
---------------
<?php
trait SomeTrait {}

class SomeClass {
  use SomeTrait;
}

$a = new SomeClass();

var_dump(is_a($a,'SomeTrait'));

Expected result:
----------------
bool(true)

Actual result:
--------------
bool(false)


------------------------------------------------------------------------



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