Edit report at https://bugs.php.net/bug.php?id=55738&edit=1

 ID:                 55738
 Updated by:         larue...@php.net
 Reported by:        vlado107 at yahoo dot com
 Summary:            intval IP address
 Status:             Bogus
 Type:               Bug
 Package:            Unknown/Other Function
 Operating System:   Win
 PHP Version:        5.3.8
 Block user comment: N
 Private report:     N

 New Comment:

(number)127.0.1.1 = (number) 127.0 = (int) 127
(number)127.1.1.1 = (number) 127.1 = (float) 127.1


Previous Comments:
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[2011-09-20 21:49:18] vlado107 at yahoo dot com

(number) 127.1.1.1 = 127.1
Yes, this is ok.
$ip = '127.1.1.1';
echo $ip == intval($ip); 
Ti is false and it should be false because 127.1.1.1 is not equal with 127.1

Problem is if IP is 127.0.1.1

$ip = '127.0.1.1';
echo $ip == intval($ip); // true

This is  127.0.1.1 == 127.0 and it is true. How it can be true? It should be 
false like in first case.

------------------------------------------------------------------------
[2011-09-20 11:27:00] larue...@php.net

sorry, typo.

(number) 127.1.1.1 = 127.1

------------------------------------------------------------------------
[2011-09-20 11:25:59] larue...@php.net

Thank you for taking the time to write to us, but this is not
a bug. Please double-check the documentation available at
http://www.php.net/manual/ and the instructions on how to report
a bug at http://bugs.php.net/how-to-report.php

(number) 127.1.1.1  = 127.0

------------------------------------------------------------------------
[2011-09-20 10:02:53] vlado107 at yahoo dot com

Description:
------------
Problem in some cases when use intval($ip);


Test script:
---------------
$ip = '127.0.1.1';
echo $ip == intval($ip); // true

$ip = '127.1.1.1';
echo $ip == intval($ip); // false

Expected result:
----------------
Both result should be false



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