Edit report at https://bugs.php.net/bug.php?id=51184&edit=1
ID: 51184
Comment by: asdf at asdf dot com
Reported by: s...@php.net
Summary: DateInterval has incorrect days property on windows
Status: Wont fix
Type: Bug
Package: Date/time related
Operating System: Windows
PHP Version: 5.3.2
Assigned To: pajoye
Block user comment: N
Private report: N
New Comment:
Your function can be changed to accept Datetime Objects for Strings this way.
Also now calculates datetime difference from dt1 to dt2 rather then the other
way around.
private function daysdiff($dt1, $dt2, $timeZone = 'America/Chicago')
{
$tZone = new DateTimeZone($timeZone);
if(is_string($dt1))
{
$dt1 = new DateTime($dt1, $tZone);
}
if(is_string($dt2))
{
$dt2 = new DateTime($dt2, $tZone);
}
// use the DateTime datediff function IF we have a non-buggy version
// there is a bug in many Windows implementations that diff() always
returns 6015
if( $dt1->diff($dt1)->format("%a") != 6015 ) {
return $dt1->diff($dt2)->format("%a");
}
// else let's use our own method
$y1 = $dt1->format('Y');
$y2 = $dt2->format('Y');
$z1 = $dt1->format('z');
$z2 = $dt2->format('z');
$diff = intval($y2 * 365.2425 + $z2) - intval($y1 * 365.2425 + $z1);
return $diff;
}
Previous Comments:
------------------------------------------------------------------------
[2012-02-06 21:25:02] asdf at asdf dot com
Also have this problem. A full year since last modified. No fixes yet?
I agree with the other use who said there should be more documentation on this
error. I am sure lots of us spent lots of time before we found this thread
trying to figure out why diff() does not output the correct result.
Right here would be a great place to put some documentation on the 6015 error:
http://us3.php.net/manual/en/datetime.diff.php
------------------------------------------------------------------------
[2012-01-29 05:38:54] alabi10 at yahoo dot com
The fix submitted by fbast...@yahoo.com on 2011-10-16 16:13 UTC solved the
problem
for me on Windows 7 running WAMP on localhost and php 5.3.0
------------------------------------------------------------------------
[2011-11-12 15:08:05] iskeen at barebrush dot com
I am surprised that the number of days between two dates problem is not made
clear right up front in the documentation. It took me 3 hours to find this page
and I was trying all different things to make it work. I suspected a problem
when the three different sets of dates I was using all came out with the same
answer, but when I finally used %a and they all came out with 6015, I knew,
finally, that there is a problem. The fact of the problem should be made very
clear right up front.
------------------------------------------------------------------------
[2011-10-16 16:13:05] fbastage at yahoo dot com
Here's a reasonably close substitute (run result through abs() if you don't
want potentially negative numbers):
// $dt1 and $dt2 can be any valid date string that DateTime accepts
// the time zone shouldn't affect anything (since $dt1 and $dt2 use same zone),
// but you can override the default
function daysdiff($dt1, $dt2, $timeZone = 'America/Chicago') {
$tZone = new DateTimeZone($timeZone);
$dt1 = new DateTime($dt1, $tZone);
$dt2 = new DateTime($dt2, $tZone);
// use the DateTime datediff function IF we have a non-buggy version
// there is a bug in many Windows implementations that diff() always returns
// 6015
if( $dt1->diff($dt1)->format("%a") != 6015 ) {
return $dt1->diff($dt2)->format("%a");
}
// else let's use our own method
$y1 = $dt1->format('Y');
$y2 = $dt2->format('Y');
$z1 = $dt1->format('z');
$z2 = $dt2->format('z');
$diff = intval($y1 * 365.2425 + $z1) - intval($y2 * 365.2425 + $z2);
return $diff;
}
------------------------------------------------------------------------
[2011-09-05 18:06:18] a at a dot com
Not solved with 5.3.5 on Windows.
------------------------------------------------------------------------
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