Edit report at https://bugs.php.net/bug.php?id=39588&edit=1
ID: 39588
Comment by: su dot hang at yahoo dot com
Reported by: pprasse at actindo dot de
Summary: unpack("a*", "abc\0") does not work as expected
Status: Not a bug
Type: Bug
Package: Strings related
Operating System: linux 2.6.10
PHP Version: 4.4.4
Block user comment: N
Private report: N
New Comment:
is this also expected behavior?
<?php
$var = "str";
$packed = pack("a5", $var); // 5 bytes long NULL-padded string
var_dump(unpack("a5", $packed));
array(1) {
[1]=>
string(3) "str"
}
Previous Comments:
------------------------------------------------------------------------
[2006-11-22 14:23:04] [email protected]
Expected behaviour.
$var = "str";
$packed = pack("a5", $var); // 5 bytes long NULL-padded string
var_dump(unpack("a*", $packed)); // the NULL-padding is removed to get the
original data.
------------------------------------------------------------------------
[2006-11-22 14:09:26] pprasse at actindo dot de
Description:
------------
unpack( "a*", $string ) does not work as expected when last character of
$string is "\0"
Reproduce code:
---------------
<?php
$string = "abc\0";
$arr = unpack( "a*buf", $string );
printf( "strlen = %d\n", strlen($arr['buf']) );
printf( "hex dump:\t" );
for( $i=0; $i<strlen($arr['buf']); $i++ )
printf( " %02x", ord($arr['buf']{$i}) );
printf( "\n" );
?>
Expected result:
----------------
strlen = 4
hex dump: 61 62 63 00
Actual result:
--------------
strlen = 3
hex dump: 61 62 63
------------------------------------------------------------------------
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Edit this bug report at https://bugs.php.net/bug.php?id=39588&edit=1
