Edit report at https://bugs.php.net/bug.php?id=61188&edit=1

 ID:                 61188
 User updated by:    antickon at gmail dot com
 Reported by:        antickon at gmail dot com
 Summary:            Assignment changes order of evaluation of binop
                     expression
 Status:             Not a bug
 Type:               Bug
 Package:            Variables related
 Operating System:   linux
 PHP Version:        5.3.10
 Block user comment: N
 Private report:     N

 New Comment:

I'm afraid you're mistaken. The brackets denote a change in expression binding, 
not evaluation order. If what you are saying is true

<?php
function a(){echo 'a';}
function b(){echo 'b';}
a() == (b());

would output ba since the bracketed expression would be evaluated first. 
However 
it (correctly) outputs ab.

In fact, the brackets are completely irrelevant. I added them for clarity. 
Consider the equivalent example:

<?php
$a = 3;
var_dump( $a == $a = 3 );


Previous Comments:
------------------------------------------------------------------------
[2012-02-26 18:16:37] ras...@php.net

You are outsmarting yourself here. Look at your brackets.

$a == ($a=4)  

So we do the bracketed expression first: $a=4 which sets $a to 4 obviously and 
returns the value 4. So what are we left with?

$a == 4

But what is $a at this point? Well, it is 4 of course, because we just set it. 
So we have:

4 == 4

If you can find a language where this expression doesn't return true, 
regardless 
of the initial value of $a, then you should file a bug against that language.

------------------------------------------------------------------------
[2012-02-26 17:54:18] antickon at gmail dot com

Description:
------------
An assignment expression can change the order of operation for == and != (and 
possibly other binops)

Test script:
---------------
<?php
$a = 3;
var_dump( $a == ( $a = 4 ) );

Expected result:
----------------
bool(false)

evaluation of $a == ( $a = 4 ) should be as follows:
left side of the comparison is evaluated (evaluates to 3)
right side of the comparison is evaluated (4 is assigned to $a, evaluates to 4)
3 == 4 finally evaluates to false

Actual result:
--------------
bool(true)


------------------------------------------------------------------------



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