ID: 21912
Comment by: [EMAIL PROTECTED]
Reported By: [EMAIL PROTECTED]
Status: Verified
Bug Type: GetImageSize related
Operating System: Linux
PHP Version: 4.3.1-dev
New Comment:
php -r '$size =
getimagesize("http://s005.pictura-dp.nl/foto/500px/GAM_908/08841.jpg");
print_r($size); echo "\n";'
works without problems here (PHP 4.3.0), while
php -r '$size =
getimagesize("http://s005.pictura-dp.nl/foto/500px/GAM_017/00645.jpg");
print_r($size); echo "\n";'
prints nothing. ImageMagick's "identify" sees some strange ipct data in
the second image; probably these make getimagesize() misbehave.
Previous Comments:
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[2003-01-27 17:25:35] [EMAIL PROTECTED]
I can reproduce this with latest stable CVS (4.3.1-dev)
It does work if the image is local..but not if it's remote.
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[2003-01-27 16:12:37] [EMAIL PROTECTED]
Hallo,
I have a weird problem, which I think is a bug. The following script
works with PHP 4.1.2 (I know, very outdated), but DOES NOT work with
PHP 4.3.0:
<?
error_reporting (E_ALL);
$foto="http://s005.pictura-dp.nl/foto/500px/GAM_908/08841.jpg";
$image_size=getimagesize($foto);
$width=$image_size[0];
$height=$image_size[1];
$type=$image_size[2];
print ("<img src='$foto'>\n");
print ("<p>\n");
print ("width: $width; height: $height; type: $type<br>\n");
print ("<p>\n");
$foto="http://s005.pictura-dp.nl/foto/500px/GAM_017/00645.jpg";
$image_size=getimagesize($foto);
$width=$image_size[0];
$height=$image_size[1];
$type=$image_size[2];
print ("<img src='$foto'>\n");
print ("<p>\n");
print ("width: $width; height: $height; type: $type<br>\n");
?>
The problem is :
The first image works fine, it shows the height, width and type.
However, the information about the second image is only beeing
displayed if using PHP 4.1.2. With PHP 4.3.0 no information is beeing
displayed.
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Edit this bug report at http://bugs.php.net/?id=21912&edit=1