ID:               24515
 User updated by:  phpbug at easihosting dot co dot uk
 Reported By:      phpbug at easihosting dot co dot uk
-Status:           Feedback
+Status:           Open
 Bug Type:         *General Issues
 Operating System: linux
 PHP Version:      4.3.3RC1
 New Comment:

What information do you require? I have read the guidelines, and I seem
to have adeared to them, short, simple and not missing anything out.

Did you not understand my bug report or do you think it is not a bug
but a feature?

Everytime I get a visitor to my site it sends me an email. It is
reporting that they are visiting a different site to what they are.
This other site is also hosted on the same server.

I have not found a way to easily reproduce this, I just have to wait
and read the emails that report both $_SERVER array and registered
global variables.


Previous Comments:
------------------------------------------------------------------------

[2003-07-07 06:14:42] [EMAIL PROTECTED]

Not enough information was provided for us to be able
to handle this bug. Please re-read the instructions at
http://bugs.php.net/how-to-report.php

If you can provide more information, feel free to add it
to this bug and change the status back to "Open".

Thank you for your interest in PHP.




------------------------------------------------------------------------

[2003-07-06 17:50:44] phpbug at easihosting dot co dot uk

Description:
------------
When register_globals is on one would expect the registered globals to
be the same values as the variables accessed through the global
arrays.

$remote_addr doesn't always return the IP of the visitor to the site
but the IP of another visitor to another site on the same server.

$server_name doesn't always return the host name for the site being
visited, but that of another site being hosted on the same server.

Reproduce code:
---------------
        echo '$SERVER_NAME';
        echo " ";
        echo "$SERVER_NAME";
        echo "<br>";

        echo '$_SERVER[SERVER_NAME]';
        echo " ";
        echo "$_SERVER[SERVER_NAME]";
        echo "<br>";


Expected result:
----------------
$SERVER_NAME www.p800.co.uk
$_SERVER[SERVER_NAME] www.p800.co.uk

Actual result:
--------------
$SERVER_NAME www.p800.co.uk
$_SERVER[SERVER_NAME] www.symbos.co.uk


------------------------------------------------------------------------


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