ID: 26234
Updated by: [EMAIL PROTECTED]
Reported By: spock1985 at homail dot com
-Status: Open
+Status: Bogus
Bug Type: MySQL related
Operating System: Win Xp
PHP Version: 4.3.4
New Comment:
your code logic is flawed. you fetch twice before taking
any action. drop the first '
$row = mysql_fetch_array($result);' an you should be fine.
Previous Comments:
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[2003-11-13 00:34:24] spock1985 at homail dot com
Description:
------------
When using a while loop such as in the example below:
It skips over the very first entry within the table.
Say I have 5 rows which have a lvl of 3, when printing out the name of
said row, only the last 4 will print out.
Reproduce code:
---------------
mysql_connect (localhost, root, '');
mysql_select_db (Arakaron);
$result=mysql_query ("SELECT * FROM magic WHERE lvl='3'");
$row = mysql_fetch_array($result);
while ($row = mysql_fetch_array($result))
{
print $row['name'];
}
Expected result:
----------------
I expect to see all 5 names of the rows instead of the last 4.
Actual result:
--------------
Only shows the very last 4 rows which have a level of 3.
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Edit this bug report at http://bugs.php.net/?id=26234&edit=1
