ID: 26818
Updated by: [EMAIL PROTECTED]
Reported By: php at richardneill dot org
Status: Open
-Bug Type: CGI related
+Bug Type: Feature/Change Request
Operating System: Linux (Mandrake)
PHP Version: 4.3.4
New Comment:
The function uses the GNU getopt function, so the behaviour is exactly
same. Moved the FRs.
Previous Comments:
------------------------------------------------------------------------
[2004-01-06 17:53:42] php at richardneill dot org
I agree with you about the manual. BUT, nevertheless, this is not the
behaviour that it should have. Currently, it isn't consistent with the
normal (GNU-like) command line behaviour.
If options -x and -y are supposed to take values, then if I enter the
command:
./getopt.php -a -x -y bar
it can mean only one of 2 things:
1)I, the user have made a mistake at the command line, and omitted the
value for $x. The script should be able to test for this as an error.
2)I meant to assign a null or false value to $x
(possible, not likely)
It is *very* unlikely that I meant to assign the value '-y' to $x. (If
I had meant to do this, I would have double quoted it).
Please can we at least have an option within getopts to parse options
in a standard manner? I'd suggest doing the following:
----------------
If an option expects a value, read along the command line
until reaching the next '-' or the end of line. This value (or false if
it is null) is placed in the options_array.
----------------
Thank you.
Richard
------------------------------------------------------------------------
[2004-01-06 17:30:17] [EMAIL PROTECTED]
RTFM: "It does not matter if an argument has leading white space." (it
means also: whitespace is omitted)
------------------------------------------------------------------------
[2004-01-06 14:52:41] php at richardneill dot org
Description:
------------
When parsing options, if the command line arguments are WRONG, php
mangles them in such a way as to give an incorrect, but valid
response.
Eg my program normally takes arguments:
./getopt.php -a -x foo -y bar
(ie. option a takes no value; options x,y take values)
Therefore, if I run it as
./getopt.php -a -x -y bar
this is clearly a mistake: I omitted the value for -x.
HOWEVER, php assumes that I wanted the value for -x to be '-y'
If this is "a feature, not a bug", it might be worth documentig it, or
providing a switch to enable the behaviour I'd expect. Thank you.
Reproduce code:
---------------
#!/usr/bin/php
<?
$flags="ax:y:";
$options_array=getopt($flags);
echo "Here are the results of getopt:\n";
foreach ($options_array as $key => $value){
echo "\tkey:\t $key\t value is:\t $value";
if ($value===false){
echo "\t[FALSE]";
}
echo "\n";
}
echo "\n";
#N.B. If options -x and -y each expect an argument, then one might
expect
# 'getopt.php -x -y foo' to result in $key="x",$value=false;
$key="y",$value="foo"
# BUT actually, the result is $key="x",$value="-y"; and foo is left
over.
Expected result:
----------------
[rjn]$ ./getopt.php -a -x -y bar
Here are the results of getopt:
key: a value is: [FALSE]
key: x value is: [FALSE]
key: y value is: bar
Actual result:
--------------
[rjn]$ ./getopt.php -a -x -y bar
Here are the results of getopt:
key: a value is: [FALSE]
key: x value is: -y
------------------------------------------------------------------------
--
Edit this bug report at http://bugs.php.net/?id=26818&edit=1
