ID: 27938
User updated by: davelowe at davelowe dot net
Reported By: davelowe at davelowe dot net
-Status: Open
+Status: Bogus
Bug Type: Variables related
Operating System: Windows 2000 Pro
PHP Version: 4.3.5
New Comment:
Darnit, you have to:
$g_userName = 'dave';
$name = 'g_userName';
$trueName = $$name;
I needed to strip off the leading '$' to get my code to work, sorry
about the wasted bandwidth.
Previous Comments:
------------------------------------------------------------------------
[2004-04-09 22:31:08] davelowe at davelowe dot net
Description:
------------
I have a column value coming back from a mysql query that is
'%$g_userName'
Now, when I look at the column for each row and see a leading '%', I
know that the value is actually the name of a variable that exists in
my application. Here's a code snippet, where $name contains the
column's value as returned by mysql (the value is '%$g_userName'):
if (substr($name, 0, 1) == '%') {
$actualName = substr($name, 1, strlen($name) - 1);
$name = $$actualName;
}
When the code above gets executed, I get the following error:
Notice: Undefined variable: $g_userName in
C:\htdocs\ebbs\scripts\rightMenu_inc.php on line 51
I added the following immediately after the if {...} to make sure
$g_userName actually exists and contains a value:
echo $g_userName.'<br />';
And now I get the following:
Notice: Undefined variable: $g_userName in
C:\htdocs\ebbs\scripts\rightMenu_inc.php on line 51
dave
Where 'dave' is the value I had hard-coded in $g_userName.
Reproduce code:
---------------
$g_userName = 'dave';
$name = '$'.'g_userName';
$trueName = $$name;
echo $trueName;
Expected result:
----------------
dave
Actual result:
--------------
Notice: Undefined variable: $g_userName in
C:\htdocs\ebbs\scripts\pageFooter_inc.php on line 7
------------------------------------------------------------------------
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Edit this bug report at http://bugs.php.net/?id=27938&edit=1
