ID: 28118 User updated by: foospam at wp dot pl Reported By: foospam at wp dot pl -Status: Bogus +Status: Open Bug Type: *General Issues Operating System: * PHP Version: * New Comment:
Hey, that IS bug, because I want to use NOT RESERVED WORD, and parser causes an error! I have checked everything related with constants in PHP Manual (language -> constants, list of predefined constants, list of parser tokens, list of reserved words, EVEN LIST OF FUNCTIONS AND THEIR ALIASES), and there is no "INT" constant or anything related with it described! BTW, "INT" constant name SHOULD WORK EVEN, if there is already registered function with that name - I've checked: constant "is_int" does work. I know: there is a cast: `(int)', but: array(int) is different from (int) $foo parser should recognize, that my "INT" is user-defined constant, because I want to use it as the array element. Previous Comments: ------------------------------------------------------------------------ [2004-04-23 09:31:57] [EMAIL PROTECTED] Thank you for taking the time to write to us, but this is not a bug. Please double-check the documentation available at http://www.php.net/manual/ and the instructions on how to report a bug at http://bugs.php.net/how-to-report.php int is a reserverd keyword (in the docs you\'ll find a list of all reserved keywords) ------------------------------------------------------------------------ [2004-04-23 09:07:00] foospam at wp dot pl Description: ------------ seems, that "INT" string is some keyword for parser. Reproduce code: --------------- define('INT', 2); $types = array(1 * INT); foreach($types as $type) { echo $type . "<br />\n"; } echo "<hr />\n"; $types = array(INT); foreach($types as $type) { echo $type . "<br />\n"; } Expected result: ---------------- 2<br /> <hr /> 2<br /> Actual result: -------------- Parse error: parse error, expecting `'('' in X on line 7. ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=28118&edit=1
