ID: 28831
User updated by: nospam0 at malkusch dot de
-Summary: ArrayObject::offsetGet() does not return a stored
ArrayObject
Reported By: nospam0 at malkusch dot de
-Status: Bogus
+Status: Open
Bug Type: Arrays related
Operating System: *
PHP Version: 5.0.*
Assigned To: helly
New Comment:
> Returning "not a reference" = "creating a copy". That's
> why.
That's why offsetGet deletes the entry?
Perhaps you didn't get what I mean and actually the
subject for this bug is wrong, so I changed it (Sorry I
was fixed on the 2D ArrayObject). Try:
<?php
$array = new ArrayObject();
$array->append('test');
var_dump($array);
$array->offsetGet(0);
var_dump($array);
?>
It will return
object(ArrayObject)#1 (1) {
[0]=>
string(4) "test"
}
object(ArrayObject)#1 (1) {
[0]=>
NULL
}
So, In my eyes it is a bug, that offsetGet deletes the
entry from the ArrayObject. It should return a copy (or
better a reference) and not touch the ArrayObject.
Previous Comments:
------------------------------------------------------------------------
[2004-06-20 11:44:18] [EMAIL PROTECTED]
Returning "not a reference" = "creating a copy". That's why. Hopefully
we are able to return references in 5.1 so we can solve this then
------------------------------------------------------------------------
[2004-06-20 05:19:38] nospam0 at malkusch dot de
> Try this code:
> <?php
>
> $array = new ArrayObject();
> $subArray = new ArrayObject();
> $array->append($subArray);
>
> $subArray->append(\'item\');
> var_dump($array);
>
> $x=$array->offsetGet(0);
> $x->append(\'item2\');
> var_dump($array);
> var_dump($x);
>
> ?>
I don't think, that the output is expected:
object(ArrayObject)#1 (1) {
[0]=>
object(ArrayObject)#2 (1) {
[0]=>
string(4) "item"
}
}
object(ArrayObject)#1 (1) {
[0]=>
NULL
}
object(ArrayObject)#2 (2) {
[0]=>
string(4) "item"
[1]=>
string(5) "item2"
}
Why is there a NULL in the second var_dump? If offsetGet()
would not return a reference I would at least expect, that
my ArrayObject won't loose its entry. It seems that
offsetGet() does the work of offsetUnset().
------------------------------------------------------------------------
[2004-06-18 20:55:21] [EMAIL PROTECTED]
Thank you for taking the time to write to us, but this is not
a bug. Please double-check the documentation available at
http://www.php.net/manual/ and the instructions on how to report
a bug at http://bugs.php.net/how-to-report.php
Unfortunatley internal functions cannot return a reference.......
Try this code:
<?php
$array = new ArrayObject();
$subArray = new ArrayObject();
$array->append($subArray);
$subArray->append(\'item\');
var_dump($array);
$x=$array->offsetGet(0);
$x->append(\'item2\');
var_dump($array);
var_dump($x);
?>
------------------------------------------------------------------------
[2004-06-18 16:19:13] nospam0 at malkusch dot de
Description:
------------
If I save an ArrayObject in an ArrayObject, I can't
manipulate the stored ArrayObject, by getting it with
offsetGet()
Reproduce code:
---------------
$array = new ArrayObject();
$subArray = new ArrayObject();
$array->append($subArray);
$subArray->append('item');
var_dump($array);
$array->offsetGet(0)->append('item2');
var_dump($array);
Expected result:
----------------
object(ArrayObject)#23 (1) {
[0]=> object(ArrayObject)#24 (1) {
[0]=> string(4) "item" } }
oobject(ArrayObject)#23 (1) {
[0]=> object(ArrayObject)#24 (1) {
[0]=> string(4) "item",
[1]=> string(5) "item2" } }
Actual result:
--------------
object(ArrayObject)#23 (1) {
[0]=> object(ArrayObject)#24 (1) {
[0]=> string(4) "item" } }
object(ArrayObject)#23 (1) { [0]=> NULL }
------------------------------------------------------------------------
--
Edit this bug report at http://bugs.php.net/?id=28831&edit=1
