ID: 33172 Updated by: [EMAIL PROTECTED] Reported By: tomas_matousek at hotmail dot com -Status: Open +Status: Bogus Bug Type: Scripting Engine problem Operating System: WinXP PHP Version: 5.0.4 New Comment:
Sorry, but your problem does not imply a bug in PHP itself. For a list of more appropriate places to ask for help using PHP, please visit http://www.php.net/support.php as this bug system is not the appropriate forum for asking support questions. Due to the volume of reports we can not explain in detail here why your report is not a bug. The support channels will be able to provide an explanation for you. Thank you for your interest in PHP. It works just like said in the manual. Previous Comments: ------------------------------------------------------------------------ [2005-06-03 23:39:10] tomas_matousek at hotmail dot com Doesn't work either. ------------------------------------------------------------------------ [2005-06-03 21:22:11] [EMAIL PROTECTED] Please try using this CVS snapshot: http://snaps.php.net/php5-STABLE-latest.tar.gz For Windows: http://snaps.php.net/win32/php5.0-win32-latest.zip ------------------------------------------------------------------------ [2005-05-28 16:30:17] tomas_matousek at hotmail dot com Well, I've swapped the expected and the actual results. I would expect all values of the array to be modified. ------------------------------------------------------------------------ [2005-05-28 16:24:41] tomas_matousek at hotmail dot com Description: ------------ The behavior of foreach statment with reference value is not imho right if the array gets modified during iteration. See the code I've pasted here. If the array is written to (either by unset or by a write operation) during iteration, the effect of & is canceled, i.e. the values are not modified since the write operation. This seems to me as bug because it is inconsistent with the "definition" of foreach which should say that foreach($a as $k => $v) {} is (more or less) equivalent to $copy_of_a = $a; while(next($copy_of_a)) { $k = key($copy_of_a); $v = $copy_of_a[$k]; } With the &, one can deduce the following "definition": foreach($a as $k =>& $v) { } is equivalent to $copy_of_a = $a; while(next($copy_of_a)) { $k = key($copy_of_a); $v =& $a[$k]; } Using =& operator, a new value should be added if it has been unset in the original array. Reproduce code: --------------- $a = array(0,1,2,3,4,5,6,7,8); $i = 0; foreach ($a as $k =>& $v) { $v+=100; if ($i++==2) { unset($a[5]); } } var_dump($a); Expected result: ---------------- array(8) { [0]=> int(100) [1]=> int(101) [2]=> int(102) [3]=> int(3) // modification of values stops here [4]=> int(4) [6]=> int(6) [7]=> int(7) [8]=> int(8) } Actual result: -------------- array(8) { [0]=> int(100) [1]=> int(101) [2]=> int(102) [3]=> int(103) [4]=> int(104) [6]=> int(106) [7]=> int(107) [8]=> int(108) [5]=> // note: the new value should be added here int(100) } ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=33172&edit=1
