ID: 34124 User updated by: ondrej at sury dot org Reported By: ondrej at sury dot org Status: Bogus Bug Type: Arrays related Operating System: Linux PHP Version: 5.0.4 New Comment:
As I stated in original bug report, it could be just lack of note in docs. I guess that problem original submitter had was, that it's pretty normal that variables in PHP can be used without initialization, it prints WARNING, but in the end it works as expected. Also documentation states that array_push has same effect as $array[] = $var, which is not true, because [] statement creates array. So I guess simple adding: "NOTE: array_push will not create array when called with non-array argument." to docs won't hurt. And it could avoid confusion on user side. Previous Comments: ------------------------------------------------------------------------ [2005-08-13 15:19:28] [EMAIL PROTECTED] Ever tried to set display_errors to On and error_reporting to E_ALL ? This is what your code outputs.: Warning: array_push(): First argument should be an array in .. I don't see any bugs here. ------------------------------------------------------------------------ [2005-08-13 15:14:15] ondrej at sury dot org Description: ------------ >From http://bugs.debian.org/289244: array_push will not create new array when called with arg which is not array type (or nonexistant). This could be just documentation error to state, that new array won't be created inside array_push(). I am not sure that there is easy fix inside PHP, since array parameter in array_push is reference and not value. So it looks like that it gets created inside array_push, but discarded (or leaked?) afterwards. Reproduce code: --------------- <?php array_push ($foo, 1, 2, 3); print ("bar $foo[0] baz\n"); ?> Expected result: ---------------- bar 1 baz Actual result: -------------- bar baz ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=34124&edit=1
