ID: 35004 User updated by: jmcentire at jackhenry dot com Reported By: jmcentire at jackhenry dot com -Status: Closed +Status: Bogus Bug Type: Variables related Operating System: Windows server 2003 PHP Version: 5.0.5 New Comment:
Changed to "bogus" Previous Comments: ------------------------------------------------------------------------ [2005-10-27 22:43:00] jmcentire at jackhenry dot com Sorry - this appears to be a problem only under MediaWiki. When ran in a test.php by itself: <?php var_dump($_SERVER["AUTH_USER"]); ?> returns the correct value with the seperator. I'll close this and pursue this with mediawiki. ------------------------------------------------------------------------ [2005-10-27 22:26:46] [EMAIL PROTECTED] Thank you for this bug report. To properly diagnose the problem, we need a short but complete example script to be able to reproduce this bug ourselves. A proper reproducing script starts with <?php and ends with ?>, is max. 10-20 lines long and does not require any external resources such as databases, etc. If possible, make the script source available online and provide an URL to it here. Try to avoid embedding huge scripts into the report. ------------------------------------------------------------------------ [2005-10-27 22:20:48] jmcentire at jackhenry dot com >> var_dump($_SERVER["AUTH_USER"]); prints string(13) "DDDDDDuuuuuuu" where DDDDDD is the 6 character domain name and uuuuuuu is the 7 character user name No seperator ------------------------------------------------------------------------ [2005-10-27 21:44:00] [EMAIL PROTECTED] what does this code print: var_dump($_SERVER["AUTH_USER"]); ? ------------------------------------------------------------------------ [2005-10-27 21:40:39] jmcentire at jackhenry dot com Description: ------------ php_info() shows server variable AUTH_USER in correct format: DOMAIN\username However, the $_server["AUTH_USER"] in code returns "DOMAINusername" (no seperator). Reproduce code: --------------- list($domain,$username) = split('[\]',$_SERVER["AUTH_USER"],2); print "Domain: $domain UserName: $username"; Expected result: ---------------- Domain: DOMAIN UserName: username Actual result: -------------- Domain: DOMAINusername UserName: ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=35004&edit=1