ID:               36029
 Updated by:       [EMAIL PROTECTED]
 Reported By:      f dot engelhardt at 21torr dot com
 Status:           Bogus
 Bug Type:         Variables related
 Operating System: Linux
 PHP Version:      5.1.2
 New Comment:

And this works fine:

$foo = NULL;
bTest( $foo );


Previous Comments:
------------------------------------------------------------------------

[2006-01-16 09:45:02] [EMAIL PROTECTED]

Yes, but PHP is not C and references are not pointers.

------------------------------------------------------------------------

[2006-01-16 09:35:10] f dot engelhardt at 21torr dot com

Description:
------------
In C and most other programming languages it is possible to parse NULL
as a reference parameter to a function (a NULL-Pointer). In PHP i need
to allocate a variable, that can be given to the function. So there is
no way to parse a NULL-Pointer.

Reproduce code:
---------------
<?php

function bTest(&$paData)
{
  if (is_null($paData))
  {
    // cleanup
    return true;
  }
  // handle data
  return true;
}

bTest(NULL);

?>

Expected result:
----------------
Should work

Actual result:
--------------
Fatal error: Cannot pass parameter 1 by reference in ...


------------------------------------------------------------------------


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