ID: 36837 User updated by: tz at universale dot hu Reported By: tz at universale dot hu Status: Bogus Bug Type: *General Issues Operating System: Windows XP PHP Version: 5.1.2 New Comment:
I double-checked the documentation and found nothing related to this problem. In a similar case, in the code i submit now, the destructor is _not_ called. So, what is the difference? Yours sincerely tz class foo { function __construct(){ throw new Exception( "foomessage" ); } function __destruct(){ sleep( 5 ); } } try { $f = new foo(); } catch ( Exception $e ){ die; } Previous Comments: ------------------------------------------------------------------------ [2006-03-23 21:00:31] [EMAIL PROTECTED] Thank you for taking the time to write to us, but this is not a bug. Please double-check the documentation available at http://www.php.net/manual/ and the instructions on how to report a bug at http://bugs.php.net/how-to-report.php the destructor is called during the script shutdown ------------------------------------------------------------------------ [2006-03-23 20:47:12] tz at universale dot hu Description: ------------ Normally, if the constructor throws an exception, the destructor is not called reaching the end of the script. That's OK In the code attached, the destructor is called. There are two important parts of the code: 1. The exception must be generated by an object called from the foo's constructor. 2. It has to handle this exception, and call 'die' In this case, the foo-s destructor is called. Reproduce code: --------------- class foo { function __construct(){ new thrower( this ); } function __destruct(){ sleep( 5 ); } } class thrower { function __construct(){ try { throw new Exception( "foomessage" ); } catch ( Exception $e ){ die; } } } $f = new foo(); Expected result: ---------------- the destructor mustn't be called ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=36837&edit=1