ID:               36930
 Updated by:       [EMAIL PROTECTED]
 Reported By:      ante at abstraktmedia dot com
-Status:           Open
+Status:           Bogus
 Bug Type:         SPL related
 Operating System: Win XP
 PHP Version:      5.1.2
 New Comment:

Thank you for taking the time to write to us, but this is not
a bug. Please double-check the documentation available at
http://www.php.net/manual/ and the instructions on how to report
a bug at http://bugs.php.net/how-to-report.php

if (($foo instanceof ArrayObject) || is_array($foo))


Previous Comments:
------------------------------------------------------------------------

[2006-03-31 11:46:51] ante at abstraktmedia dot com

Description:
------------
OK...

I'm using ArrayObject quite a lot and I experienced something which is
not logical...

If I have

$arrayObj = new ArrayObject(Array("Test"))

function is_array() returns false which is not ok in the first
place...but never mind...we'll cast it to array so we use

if(is_array((array) $arrayObj)) .....

but the problem is what if $arrayObj is not Array...what if it's null
or string? casting to array will make the function 
return true even if the variable is null....

That's the real problem....

Shor story...I cannot use is_array on ArrayObject if I don't cast that
object to a "normal" array..But if I use casting and variable is for
example string then is_array will return true when it should return
false.... 



Reproduce code:
---------------
Logicaly:

$arrayObj = new ArrayObject(Array("Test"));

//we don't use casting!!
if(is_array($arrayObj)) ... should return TRUE

but because of the internal workings of PHP we have to convert
ArrayObject to Array before sending it to is_array function...

But what if our Array is String actually...??or Null???
Because we HAVE TO cast that ArrayObject before sending it to is_array
it will also cast String or anything else to an Array and therefore
function will return TRUE...


$arrayObj = new ArrayObject(Array("Test"));
//$arrayObj = null;

if(is_array((array) $arrayObj)) {
        print("Is array!");
}
else {
        print("Not array!");
}

Now try uncommeting second line and commenting first...



------------------------------------------------------------------------


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