ID: 36938
Updated by: [EMAIL PROTECTED]
Reported By: daniele_dll at yahoo dot it
-Status: Open
+Status: Bogus
Bug Type: Scripting Engine problem
Operating System: Windows XP SP2 - Fedora Core 4
PHP Version: 5.1.2
New Comment:
0 == 0. This is expected.
No bug here.
Previous Comments:
------------------------------------------------------------------------
[2006-04-01 09:34:00] daniele_dll at yahoo dot it
ops, forgotten to re-open the report
sorry
------------------------------------------------------------------------
[2006-04-01 09:33:18] daniele_dll at yahoo dot it
I'll try to explain me ...
$value = 'qwerty';
$value -> qwerty
(int)$value -> 0
so ... how can be that 0 is equal to qwerty?
Try this code too
<?php
$valore = 'qwerty';
$_v = intval($valore);
echo ($valore) ? 'true ' : 'false ';
echo ($_v) ? 'true ' : 'false ';
if ($valore == $_v)
{
echo "variable ({$valore}) contains a valid numeric value ({$_v})
!";
}
else
{
echo "variable doesn't contains a valid numeric value!";
}
?>
The result is wrong!
------------------------------------------------------------------------
[2006-03-31 23:25:52] [EMAIL PROTECTED]
Thank you for taking the time to write to us, but this is not
a bug. Please double-check the documentation available at
http://www.php.net/manual/ and the instructions on how to report
a bug at http://bugs.php.net/how-to-report.php
------------------------------------------------------------------------
[2006-03-31 23:17:23] daniele_dll at yahoo dot it
Description:
------------
Type casting a value on an if doesn't work!
If i compare a string value with the same value type casted to an int
and this string doesn't contains a numeric value i recive a true from
the boolean expression!
I've tried many combinations but all return the same result
Thanks for the help
Reproduce code:
---------------
<?php
$valore = 'qwerty';
if ($valore == (int)$valore)
{
echo "variable contains a valid numeric value!";
}
else
{
echo "variable doesn't contains a valid numeric value!";
}
?>
Expected result:
----------------
$valore == (int)$valore --> FALSE
variable doesn't contains a valid numeric value!
Actual result:
--------------
$valore == (int)$valore --> TRUE
variable contains a valid numeric value!
------------------------------------------------------------------------
--
Edit this bug report at http://bugs.php.net/?id=36938&edit=1
