ID: 37263
User updated by: dbeckham at dealnews dot com
Reported By: dbeckham at dealnews dot com
Status: Open
Bug Type: Scripting Engine problem
Operating System: Linux (2.6.14)
PHP Version: 5.1.2
New Comment:
You are still missing my point. How can curly braces no longer be a
special character, yet escaping them *changes* the behavior of PHP?
If {$test} produces only the value of $test without curly braces, how
on earth can \{$test} not produce the value of $test with a backslash
in front of it?
Is a curly brace special or not?
If you are not a PHP developer and do not have the ability to change
the status of this ticket and officially say that this bug will or will
not be corrected, please move on. I'm not interested in a 3rd party
debate about this issue.
Previous Comments:
------------------------------------------------------------------------
[2006-05-01 20:56:29] judas dot iscariote at gmail dot com
php -r '$test = array(array(0,1), array(2,3)); echo
"\{$test[1][0]}\n";'
outputs in PHP 4.3.11 and PHP 4_4 dev
{Array[0]}
in PHP 5_1 CVS outputs
\{Array[0]}
is consistent with the mentioned change, it just output the slash now.
but seems that it may output "\2" as you said,however, that will be
another behaviour change, and Im sure we don't want that right ?
this seems to be a documentation problem
------------------------------------------------------------------------
[2006-05-01 20:09:11] dbeckham at dealnews dot com
Here is another example to highlight the problem:
php -r '$test = array(array(0,1), array(2,3)); echo
"{$test[1][0]}\n";'
This should produce the following output:
2
php -r '$test = array(array(0,1), array(2,3)); echo
"\{$test[1][0]}\n";'
This produces:
\{Array[0]}
Since curly braces are no longer special characters, should not echo
"\{$test[1][0]}\n"; produce the following?
\2
------------------------------------------------------------------------
[2006-05-01 20:01:32] dbeckham at dealnews dot com
I disagree, this *is* a bug. You can't have it both ways, either the
curly brace is not a special character and does not need to be escaped,
or it is a special character used for complex variables and can be
escaped. What you have right now is neither ... it's a special
character and removed from the output when used with a complex
variable, but if escaped, it's not used with the complex variable and
additionally the backslash is added to the output.
By the way, my intention was never to produce {$ in the output, but
only to make sure the curly brace was output along with the variable.
------------------------------------------------------------------------
[2006-05-01 19:32:26] judas dot iscariote at gmail dot com
this is not a bug, it's a behaviour change of the engine.
see.
http://bugs.php.net/bug.php?id=35527
and the documentation here:
"Before PHP 5.1.1, backslash in \{$var} hasn't been printed."
"(Use "{\$" to get a literal "{$")." [1]
[1] http://php.net/manual/en/language.types.string.php
------------------------------------------------------------------------
[2006-05-01 15:36:29] dbeckham at dealnews dot com
Description:
------------
When escaping curly braces in a string, the backslash characters are
included in any output.
Reproduce code:
---------------
<?
$test = "test";
echo "\{$test\}\n";
?>
Expected result:
----------------
The above output should be:
{test}
Actual result:
--------------
The actual output is:
\{test\}
------------------------------------------------------------------------
--
Edit this bug report at http://bugs.php.net/?id=37263&edit=1
