ID: 38043
Updated by: [EMAIL PROTECTED]
Reported By: aeolianmeson at blitzeclipse dot com
-Status: Open
+Status: Bogus
Bug Type: Sockets related
Operating System: Fedora 4
PHP Version: 5.1.4
New Comment:
And it is PHP problem because .?. ?
This is what getsockname() returns, socket_getsockname() is just a
wrapper.
Previous Comments:
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[2006-07-09 03:47:37] aeolianmeson at blitzeclipse dot com
Description:
------------
I am connecting to myself and then closing, to sniff out available
ports on my system that I can use-- I'm sure you're acquainted with
this method.
It should always produce a different port (nPort), since no connection
is erected (because it's UDP), but it always returns that it is on the
SAME port.
Dustin Oprea
Reproduce code:
---------------
$n = 10;
while($n--)
{
$strIP = $nPort = -1;
$Socket = socket_create(AF_INET, SOCK_DGRAM, SOL_UDP);
socket_connect($Socket, '172.0.0.1', 8400);
socket_getsockname($Socket, $strAddr, $nPort);
socket_close($Socket);
print("> Available port: $strAddr:$nPort\n");
}
Expected result:
----------------
It produces ten lines of output, that should each contain one unique,
available port number.
Actual result:
--------------
Each line indicates the same port, even if a socket has been opened for
listening on it.
The problem I am having, therefore, is that I sniff the next available
port from this code, and set up a listener on it. I then do the same
thing again in order to open another listener on a different port, but
it always returns to me the same port number, and I can not not bind
it, obviously.
Is this intended?
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Edit this bug report at http://bugs.php.net/?id=38043&edit=1
