ID: 38215
Updated by: [EMAIL PROTECTED]
Reported By: php at elitecoders dot com
-Status: Open
+Status: Wont fix
Bug Type: Scripting Engine problem
Operating System: CentOS
PHP Version: 4.4.2
New Comment:
Parse error: syntax error, unexpected '=', expecting ')'
You have to update your PHP version if you want to use this syntax.
Previous Comments:
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[2006-07-26 05:32:29] php at elitecoders dot com
Description:
------------
When a function argument list contains a variable reference
which has a default value, there is no output. It may be
because of a crash, but I was unable to test for that because
I don't have access to the log files.
This reproduce code works as expected in php 5.
Reproduce code:
---------------
<?php
function exec_bug(&$var_ref = NULL) {
}
echo "working.";
?>
Expected result:
----------------
working.
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Edit this bug report at http://bugs.php.net/?id=38215&edit=1