ID:               38824
 Updated by:       [EMAIL PROTECTED]
 Reported By:      tklingenberg at lastflood dot com
-Status:           Open
+Status:           Wont fix
 Bug Type:         Feature/Change Request
 Operating System: win32
 PHP Version:      5.1.6
 New Comment:

It's just impossible.
settype() function accepts the first parameter by reference.
See fo example:
<?php

function create_a_var(&$var) {
  $var = 'created';
}
create_a_var($doesnt_exist); // you would not expect a NOTICE here,
right?
?>
settype() does the same.


Previous Comments:
------------------------------------------------------------------------

[2006-09-14 11:07:13] tklingenberg at lastflood dot com

Description:
------------
In case a program uses an uninitialized variable passed to settype(),
it should throw a Notice, compareable to echo; intval() and other
variable related functions.

Even if PHP does everything right ($var is a variable you can change
the type of), for the PHP User, it's highly possible she/he made an
error and typed in the wrong variable name. Afterwards the type of the
variable is unchecked, which can lead to even more critical errors.

All this is unnoticed because PHP does not throw a NOTICE.

Reproduce code:
---------------
<?php
$r = settype($var, "float");
?>

Expected result:
----------------
It should throw a Notice

Actual result:
--------------
No Notice is giving that $var is not initialized.


------------------------------------------------------------------------


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