In article <[EMAIL PROTECTED]>,
[EMAIL PROTECTED] (Liz Bander) wrote:
> I am getting a parse error for the return line every time I try and view
> the page. Can anyone tell me why? The code is below.
>
> $results = "select req, source, number from orders where req=" .
> $GLOBALS["req"] . ", source=" . $GLOBALS["source"] . ",
> number=" .$GLOBALS["req"] . "";
>
> if (mysql_fetch_row($results) != 0) {
> return "This has already been added.";
Is this inside a function? 'Cuz AFAIK a "return" would only make sense
inside a function.
FWIW, the comparison of the fetched row to zero strikes me as a bit
unusual. Are you just checking whether there was no rows were returned by
the query? If so, I suspect that checking mysql_num_rows() would be more
efficient.
> Also (since this is part of the problem, I'm sure) how do I take the
> $GLOBALS values and set them equal to the req and source values in the
> select statement? Is this syntax correct?
Depends. MySQL needs string values quoted too, so if for example all of
those variables are strings you'd do something like:
$results = "select req, source, number from orders where req='" .
$GLOBALS["req"] . "', source='" . $GLOBALS["source"] . ", number='" .
$GLOBALS["req"] . "'";
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