It still not working
I want to get the result of people with the first later is "A" in my database
Here is my syntax :
$result = mysql_query("SELECT * FROM mydata WHERE name like '$begin'%",$db);
the $begin is from the URL link
www.sample.com/name?begin=a
Thanks
--- "Frank M. Kromann" <[EMAIL PROTECTED]>
> wrote:
>wyoy could use a SQL statement like this:
>
>select * from myTable where LastName like "A%"
>
>- Frank
>
>> Guys,
>>
>> How to view the result from the table.
>> If I only want to display persons begin with letter A in the front.
>>
>>
>>
>> _____________________________________________________________
>> www.kaskus.com - FREE EMAIL SERVICE
>>
>> --
>> PHP Database Mailing List (http://www.php.net/)
>> To unsubscribe, e-mail: [EMAIL PROTECTED]
>> For additional commands, e-mail: [EMAIL PROTECTED]
>> To contact the list administrators, e-mail: [EMAIL PROTECTED]
>>
>>
>>
_____________________________________________________________
www.kaskus.com - FREE EMAIL SERVICE
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
To contact the list administrators, e-mail: [EMAIL PROTECTED]