Thanks, but it wont work.
I have eliminate the space but still the same message.
I have realized that the problem is below that line:
the problem is pointing to the line where i fetch the first variable:
$nombre=$myrow("nombre");
Any other Ideas????
thanks
<?
echo "Resultados de tabla Empresas";
echo"<br>";
$link = mysql_connect ("localhost:3306", "root", "")
or die ("Could not connect");
print ("Connected successfully");
mysql_select_db ("seguros");
$sql="select * from mae_companias";
$result=mysql_query($sql,$link);
echo "<table
align='center'><tr><td></td>Nombre<td>Direccion</td><td>Telefono</td><td>Fax
</td>";
$num=mysql_num_rows($result);
$cur=1;
while($num>=$cur){
$myrow=mysql_fetch_array ($result);
$nombre=$myrow("nombre");
$direccion=$myrow("direccion");
$telefono=$myrow("telefono");
$fax=$myrow("fax");
echo
"<tr><td>$nombre</td><td>$direccion</td><td>$telefono</td><td>$fax</td>";
$cur++;
}
echo "</table>";
?>
----- Original Message -----
From: leo g. divinagracia iii <[EMAIL PROTECTED]>
Cc: <[EMAIL PROTECTED]>
Sent: Tuesday, July 24, 2001 7:52 PM
Subject: Re: [PHP-DB] Problem with my first script
> i havent tested it yet... but...
>
> Fernando Gonzalez wrote:
> >
>
> > $num=mysql_num_rows($result);
> > $cur=1;
> > while($num>=$cur){
> > $myrow=mysql_fetch_array ($result);
> ^^
>
> you got a space after the function and the open paren. NO SPACES!!!!
> (as i found before that took about 10 minutes of debugging on a similar
> debugging session...) ;-)))
>
>
> --
> Leo G. Divinagracia III
> [EMAIL PROTECTED]
>
> --
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