No no no, what you want to do is echo $row[0], not <img src=$row[0]>.
$row[0] is the actual jpeg data, and the browser will interpret it like that
since you put the header("Content-type: text/jpeg");
Try echoing $row[0] only and tell me how that goes.
-- David
-----Original Message-----
From: Mark Gordon [mailto:[EMAIL PROTECTED]]
Sent: Sunday, July 29, 2001 1:31 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Still trying to get image from /tmp path
Thanks, David. That helped a little but now what I get is:
<img src=/tmp/phpMVWr5Z> in the output.
The tmp folder is up the directory tree outside of my www folder (on my
web host's 'puter)- I don't have direct access to it.
Heres the modified code:
$sql=mysql_query("SELECT bin_data FROM binary_data WHERE id=4");
$row = mysql_fetch_array($sql);
header("Content-type: image/jpeg");
echo "<img src=$row[0]>";
How can I use the path stored in the db to retrieve the image?
=====
Mark
[EMAIL PROTECTED]
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