scratch that, i had a syntax error in the array..
you were completely right dobromir eval() works perfectly..
thanks!!!!!


Brendan wrote:

> thanks dobromir,
> unfortunately that doesnt seem to work  ...
> although looking at the php manual you seem to be on the right track..
> could the way the textfield is parsed & passed back affect the array?
> 
> cheers!
> brendan
> 
> Dobromir Velev wrote:
> 
>> Hi,
>> I think you can use the eval() function to execute the stored info. 
>> The code
>> will look something like this
>> $res=mysql_query(...)
>> eval($row_from_query);
>>
>> If you want to change the name of the array you could use
>> eval(str_replace("$array","$newarray",$row_from_query));
>>
>> HTH
>> Dobromir Velev
>>
>> -----Original Message-----
>> From: brendan <[EMAIL PROTECTED]>
>> To: [EMAIL PROTECTED] <[EMAIL PROTECTED]>
>> Date: Thursday, September 13, 2001 2:20 PM
>> Subject: [PHP-DB] array in db field -> actual array
>>
>>
>>
>>> hi,
>>> i am currently scouring the web for a solution to this but thought i
>>> would try here as well ..
>>>
>>> i have a text field in a mysql database
>>> the textfield contains an array written out as
>>> //--------------------
>>> $array[0][1]="one";
>>> $array[0][2]="two";
>>> $array[0][3]="thre";
>>> $array[1][1]="four";
>>> $array[2][1]="five";
>>> //--------------------
>>>
>>> now i need to extract this from the db .. simple
>>> and use it as an array for a function .. not as simple as i thought it
>>> would be
>>>
>>>
>>> ie
>>>
>>> $newarray =mysqlquery('etc','etc','etc')
>>> and $newarray should be
>>> $newarray[0][1]="one";
>>> $newarray[0][2]="two";
>>> $newarray[0][3]="thre";
>>> $newarray[1][1]="four";
>>> $newarray[2][1]="five";
>>>
>>> elp?
>>>
>>> cheers
>>> brendan
>>>
>>>
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>>>
>>>
>>
> 


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