Please could some take a look at this code and tell me why when I take my IF statements out of the function and put in them in the same place where I call the function from they work, but as soon as I replace them with the function name they don't?
Appreciate any help. torrent Here's the code... // Define the rating's filter <?php function RatingFilter () { if ($br) {$sql.= " and beg_rate >= '2'";} if ($ir) {$sql.= " and int_rate >= '2'";} if ($ar) {$sql.= " and adv_rate >= '2'";} if ($sr) {$sql.= " and sbd_rate >= '2'";} } ?> if ($search) { include ('logon-inc.php'); $sql = "SELECT rsrt_name, ctry_name FROM resort_tbl WHERE ctry_name='$country[0]'"; RatingFilter(); <--- If I put 'if' statement here instead it works for ($n=1; count($country) > $n; $n++){ $sql.= " or ctry_name='$country[$n]'"; RatingFilter(); <-- Or here } . . . . } -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]