the value doesn't determine whether it's checked or not - it determines the
value passed WHEN it's checked.
try the lines below:
echo"<input type=/"checkbox/" name=/"firstvalue/" value=/"1/"";
if ($result[32] == 1){
echo" checked>";
}else{
echo">";
}
or something along these lines.
-----Original Message-----
From: SpyProductions Support Team [mailto:[EMAIL PROTECTED]]
Sent: 20 December 2001 16:40
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Checkboxes, PHP, and MySQL
I've looked around in a few of the PHP lists for an answer to this, but
can't come up with one.
Here's what I am doing:
I have a form with a few checkboxes.
When the information as to whether the checkboxes are checked or not is
'saved' into the MySQL table, they are represented by a value of '1' - fine.
When I want to edit this information, in the form of a similar form with
checkboxes, the boxes are not checked off if they were before.
What I am stuck on is how a checkbox can get checked off when pulling
information from the MySQL as an array.
Here's a line of code showing my array coming out.
<input type=checkbox name=firstvalue value='$result[32]'>
$result is the array.
I guess what I am asking is that if a checkbox is assigned a value of one,
why doesn't it appear as already checked off?
Thanks,
-Mike
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