try using the rand function.. eg... $rand=rand(1,10); <input type='text' name='id$rand'>
but that migth get a same number more then once... my suggestion is this $checkboxid="1"; // Start of the loop echo "<input type='text' name='id$checkboxid'>"; // end of loop $checkboxid = $checkboxid + 1; that should work i think.... havent tested that code. but thats my idea. Neil ----- Original Message ----- From: Chris Payne <[EMAIL PROTECTED]> To: <[EMAIL PROTECTED]> Sent: Saturday, January 05, 2002 10:59 PM Subject: [PHP-DB] database/form help needed Hi there everyone, I have a loop which goes through my MySQL database and some PHP code which grabs results 9 at a time, and that works great. Now, I also have a checkbox called ID for each of the 9 entries and here is my problem. How can I dynamically assign a unique ID for my checkboxes? I am getting my checkboxes through a loop, and because of that the ID is called id - for all of my entries, so I can't select multiple as only one entry comes out on the results page. How can I dynamically create checkboxes with a unique id (Such as id1, id2 etc ...) so that I can make multiple selections from my DB? Thank you all so much - Happy New Year. Regards Chris Payne www.planetoxygene.com -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
