It may have been obvious to many, but I stumbled across the solution
(eventually)..
Changing the while statement to a do statement did the trick:
$sql = " SELECT COUNT(DateBilled) AS count, MONTH(DateBilled) AS
BilledMonth, YEAR(DateBilled) AS BilledYear FROM Invoices GROUP BY
MONTH(DateBilled) ORDER BY DateBilled DESC";
$monthly_result = mysql_query($sql, $db);
$monthly_row = DBfetch_array($monthly_result);
$i=0;
do {
$InvMonth[$i] = $monthly_row["BilledMonth"];
$InvCount[$i] = $monthly_row["count"];
echo "<strong>Month: " . date ("F", mktime(0,0,0,$InvMonth[$i],1,2002))
. " <!-- ($InvMonth) --> Number of Invoices: " . $InvCount[$i] .
"</strong><br>";
++$i;
} while($monthly_row = mysql_fetch_array($monthly_result));
On Fri, 2002-01-11 at 11:20, Mike Gifford wrote:
> Hello,
>
> Thanks for your quick reply.. I'm trying to improve the stats feature
> for gcdb (a pretty decent little PHP/MySQL accounting package on SF.net)
>
> On Fri, 2002-01-11 at 05:24, DL Neil wrote:
> > Have you posted all of the relevant code - for example, how the 'result' is
>limited to three month's worth of
> > data???
>
> I didn't provide all of the code in the initial response as it was using
> a wrapper so I didn't know how relevant it would be.. However, your
> note made me realize that I could rewrite the code without the
> wrapper.. It still worked the same way. The code stands as:
>
> $sql = " SELECT COUNT(DateBilled) AS count, MONTH(DateBilled) AS
> BilledMonth, YEAR(DateBilled) AS BilledYear FROM Invoices GROUP BY
> MONTH(DateBilled) ORDER BY DateBilled DESC";
> $monthly_result = mysql_query($sql, $db);
> $monthly_row = DBfetch_array($monthly_result);
> while($monthly_row = mysql_fetch_array($monthly_result)) {
> ++$i;
> $InvMonth[$i] = $monthly_row["BilledMonth"];
> $InvCount[$i] = $monthly_row["count"];
> echo "<strong>Month: " . date ("F",
> mktime(0,0,0,$InvMonth[$i],1,2002)) . " <!-- ($InvMonth) --> Number
> of Invoices: " . $InvCount[$i] . "</strong><br>";
> }
>
> RESULTS:
> Month: December Number of Invoices: 22
> Month: November Number of Invoices: 17
> Month: October Number of Invoices: 21
>
> > Have you extracted the SQL from the PHP and applied it directly to the command
>line or used it in a MySQL
> > Management package? Was the result any different?
>
> Also a damn good idea (I haven't had root access to MySQL until
> recently, hadn't thought of that either)
>
> mysql> SELECT COUNT(DateBilled) AS count, MONTH(DateBilled) AS
> BilledMonth, YEAR(DateBilled) AS BilledYear FROM Invoices GROUP BY
> MONTH(DateBilled) ORDER BY DateBilled DESC;
> +-------+-------------+------------+
> | count | BilledMonth | BilledYear |
> +-------+-------------+------------+
> | 15 | 1 | 2002 |
> | 22 | 12 | 2001 |
> | 17 | 11 | 2001 |
> | 21 | 10 | 2001 |
> +-------+-------------+------------+
> 4 rows in set (0.00 sec)
>
> Ok.. So the problem seems to be with my code..
>
>
> $sql = " SELECT COUNT(DateBilled) AS count, MONTH(DateBilled) AS
> BilledMonth, YEAR(DateBilled) AS BilledYear FROM Invoices GROUP BY
> MONTH(DateBilled) ORDER BY DateBilled ASC";
> $monthly_result = mysql_query($sql, $db);
> $monthly_row = DBfetch_array($monthly_result);
> $i=0;
> while($monthly_row = mysql_fetch_array($monthly_result)) {
>
> $InvMonth[$i] = $monthly_row["BilledMonth"];
> $InvCount[$i] = $monthly_row["count"];
> echo "<strong>Month: " . date ("F", mktime(0,0,0,$InvMonth[$i],1,2002))
> . " <!-- ($InvMonth) --> Number of Invoices: " . $InvCount[$i] .
> "</strong><br>";
> ++$i;
> }
>
> RESULTS:
> Month: November Number of Invoices: 17
> Month: December Number of Invoices: 22
> Month: January Number of Invoices: 15
>
> I can't see the bug in the PHP I've got, but there certainly must be
> one..
>
> Any suggestions would be appreciated!
>
> Mike
>
> > ----- Original Message -----
> > From: "Mike Gifford" <[EMAIL PROTECTED]>
> > To: <[EMAIL PROTECTED]>
> > Sent: 11 January 2002 08:12
> > Subject: [PHP-DB] GROUP BY MONTH(DateBilled) misses an entry consistently
> >
> >
> > > Hello
> > >
> > > I've got the following SQL Query, which consistently pulls up only 3 out
> > > of 4 months from the database:
> > >
> > > $sql = " SELECT COUNT(DateBilled) AS count, MONTH(DateBilled) AS
> > > BilledMonth, YEAR(DateBilled) AS BilledYear FROM Invoices GROUP BY
> > > MONTH(DateBilled) ORDER BY DateBilled ASC";
> > >
> > > This results in:
> > > Month: November Number of Invoices: 17
> > > Month: December Number of Invoices: 22
> > > Month: January Number of Invoices: 15
> > >
> > > But when I do change the order of the query from ASC to DESC like this:
> > >
> > > $sql = " SELECT COUNT(DateBilled) AS count, MONTH(DateBilled) AS
> > > BilledMonth, YEAR(DateBilled) AS BilledYear FROM Invoices GROUP BY
> > > MONTH(DateBilled) ORDER BY DateBilled ASC";$sql = " SELECT
> > > COUNT(DateBilled) AS count, MONTH(DateBilled) AS BilledMonth,
> > > YEAR(DateBilled) AS BilledYear FROM Invoices GROUP BY MONTH(DateBilled)
> > > ORDER BY DateBilled DESC";
> > >
> > > I get:
> > > Month: December Number of Invoices: 22
> > > Month: November Number of Invoices: 17
> > > Month: October Number of Invoices: 21
> > >
> > > (I gained October and Lost January)
> > >
> > > The date format in the DB is like this:
> > > 2001-12-05
> > >
> > > I've tried a whole stack of variations on the above query, but I still
> > > seem to be coming up one short. Any idea why I'm not getting a display
> > > of all of the months?
> > >
> > > Thanks.
> > >
> > > Mike
> > > --
> > > Mike Gifford, OpenConcept Consulting, http://www.openconcept.ca
> > > Supporting progressive organizations in online campaigns and tools.
> > > Feature: Women's Learning Partnership http://learningpartnership.org
> > > Truth is that which confirms what we already believe. Northrop Frye
> > >
> > >
> > > --
> > > PHP Database Mailing List (http://www.php.net/)
> > > To unsubscribe, e-mail: [EMAIL PROTECTED]
> > > For additional commands, e-mail: [EMAIL PROTECTED]
> > > To contact the list administrators, e-mail: [EMAIL PROTECTED]
> > >
> > >
> --
> Mike Gifford, OpenConcept Consulting, http://www.openconcept.ca
> Supporting progressive organizations in online campaigns and tools.
> Feature: Women's Learning Partnership http://learningpartnership.org
> Truth is that which confirms what we already believe. Northrop Frye
--
Mike Gifford, OpenConcept Consulting, http://www.openconcept.ca
Supporting progressive organizations in online campaigns and tools.
Feature: Women's Learning Partnership http://learningpartnership.org
Truth is that which confirms what we already believe. Northrop Frye
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, e-mail: [EMAIL PROTECTED]
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