Hi Markus,
I think you forgot to assign the value of ereg_replace to a variable. I made
this test and it worked:
<?
$t = 'abc*cde*';
printf("%s\n", ereg_replace("\*", "\%", $t)); // or $result =
ereg_replace("\*", "\%", $t);
?>
Hope it helps,
Bruno Pereti.
----- Original Message -----
From: "Markus Lervik" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Tuesday, January 15, 2002 7:40 AM
Subject: [PHP-DB] Replacing * with %
> Hello all!
>
> I can't for the love of god get neither ereg_replace nor str_replace
> to work. I wan't to replace * with % so I can use SELECT ... WHERE
> whatever LIKE "string%" in MySQL.
>
> I've tried ereg_replace("*","%",$search_name). Didn't work.
> I tried escaping the asterisk. I tried double-escaping the asterisk.
> I tried str_replace("*","%",$search_name), and that didn't work
> either. I tried just about everything I could think of, escaping, double-
> escaping and triple-escaping ad nauseum, but it just wont work.
>
> Oh, yes, I also tried $search_name=ereg_replace(blablabla);
> What a surprise. It didn't work.
>
> Yes, I've RTFM, RTMFM, read from my PHP Blackbook to phpbuilder.net
> and just about everything in between.
>
> Pretty soon I'll start bashing away on that Solaris 8 box over there.
>
>
> Markus - frustrated
>
> --
> Markus Lervik
> Linux-administrator with a kungfoo grip
> Vaasa City Library - Regional Library
> [EMAIL PROTECTED]
> +358-6-325 3589 / +358-40-832 6709
>
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