Hi Jen, here's some code I posted up in the general ng for storing in db and
retrieving images from db for display on your page.
It's recommended that you stay away from storing actual images in the db. If
you are storing a path the code below might help you out. It select a
firstname, and
an image according to an id. You'll have to change the "youridentityfield"
and "youridentity" values to suit your needs.





##################################### display image from db
#####################################################
#connect to db
$connectionToDBid = odbc_connect("ceo34deesnr43ipits", "joeyscode",
"joeyscode");


// sql statement
$sqlb = "SELECT imagepath, firstname FROM IMAGES WHERE youridentityfield ="
. $youridentity;

# execute the query
$resultset = odbc_do($connectionToDBid, $sqlb);

$image = odbc_result($resultset,1);
$firstname = odbc_result($resultset,2);

print "<br><br><br><div align='center'>";
print "<table width='400' border=0 cellpadding=2>" ;
print "<tr><td align='left'>" ;
print  "<font color='#ffffff' face='verdana'><h4>" . "Welcome back " .
$firstname . "</h4></font>";
print "</td></tr>";
print "<tr><td align='center'>" ;
print "<img src='" . $image."'  align='center' border='0'><br>";
print "</td></tr>";
print "</table>";

# close the db connection here

##################################### end of display image from db
#####################################################



#################################photo upload form
####################################################################

Here's a common form that allows you to upload a file (say an image) to the
db

<form action='upload.php' method='post' enctype='multipart/form-data'>
<input type='hidden' name='MAX_FILE_SIZE' value='102400'>
<P><font color='#ffffff' face='verdana' size=1>Upload Photo:</font><input
type='file' name='userfile'><input type='submit'
value='Upload!!!'></form></p>

################################end of photo upload form
##############################################################


############################start of upload process to db
################################################################
<?php

# $userfile is the file being uploaded


# print $userfile . "<BR>";
# print $userfile_name . "<BR>";

#use a time stamp plus the original file name to uniquely name the image
before storing in db to prevent two files with the same name

$timestamp = time();
$userfile_name = $timestamp.$userfile_name ;

// copy the file being posted -- remember to escape backslashes!!!
if(copy($userfile, "/ez/codesnipits/consultant/tempimages/".
$userfile_name)){
print "<font face='Verdana, Arial, Helvetica, sans-serif' color='#663399'
size='2'>Your picture has been uploaded successfully and has been made
available for
online users to view.</font><br><br><br>" ;
}
else
{
print "<font face='Verdana, Arial, Helvetica, sans-serif'
color='#663399'>Error encountered during resume upload process.</font><br>";
}

$patharola = "tempimages/". $userfile_name;

// insert path into database here
# connect to db
$connectionToDBid = odbc_connect("cdefc5onwesulertt", "joeyscon",
"joeyscon");

session_register("consultantid");
$consultantid = $consultantid;

# create query statement -- update image field in db using path
$sqlr = "UPDATE CONSULTANT SET image= '$patharola' WHERE consultantid=" .
$consultantid;
# execute the sql statement (query) on the connection made
$resultset = odbc_do($connectionToDBid, $sqlr);


?>

################################end of image to db process
##################################################


Hope this helps you out :)

Cheers Joe :)







"Jennifer Downey" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> If anyone knows of one, would someone please point me towards a good
> tutorial on storing images in a database then fetching them out again.
>
> I would really appreciate it and thanks in advance!
>
> Jen Downey
>
>



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