Ah Ha! I got it. This was a clear case of RTFM... Based on what you said, I went back and re-read page 67 of "MySQL" by Paul DuBouis and sure enough, it made sense this time...
Here is what I came up with: SELECT gamedate, gametime, divisions.name as division, t1.name as teama, t2.name as teamb FROM divisions, teams as t1, teams as t2, games WHERE games.leagueID = '$leagueID' AND t1.ID = hometeamID AND t2.ID = awayteamID group by gamedate, gametime Thanks again for all your help!! John --- DL Neil <[EMAIL PROTECTED]> wrote: > Howdy John, > > > Sorry for the lack of information in the subject > line, > > but I didn't know how else to explain it > briefly... > > =don't be sorry, re-word it! > > > I have 2 tables and they look like this: > > > > There are 2 other tables involved, but they don't > come > > into play for this portion of the problem so I > won't > > bother you with the details. > > > > Some sample data may look like this: > > > > Table: teams > > | ID | leagueID | divisionID | name | > > | 11 | 1 | 5 | Dodgers | > > | 12 | 1 | 5 | Cobras | > > | 13 | 1 | 5 | Bombers | > > > > Table: games > > | ID | leagueID | divisionID | hometeamID | > awayteamID > > | gamedate | gametime | > > | 1 | 1 | 1 | 12 | 13 > > | 2002-02-21 | 15:30:00 | > > | 2 | 1 | 1 | 11 | 12 > > | 2002-02-26 | 15:30:00 | > > > > Here's the issue... > > > > I want to be able to have it pull in the name for > each > > of the teams (home and away) from the database. My > > existing query looks like the following: > > (note: $leagueID = 1 in the following line) > > > > SELECT gdate, gtime, divisions.name as division, > > teams.name as teama, teams.name as teamb FROM > > divisions, teams, games WHERE games.leagueID = > > '$leagueID' group by gamedate, gametime > > > > This has gotten me close, but, not over the hump. > > > > As always, I hope I have explained this well > enough! > > > The missing item that might have been helpful is a > sample output of what you have so far. I'll guess > that it's > something like: > > gdate, gtime, division, teama, teamb > -02-21 15:30 1 blank blank > > If you substitute/add hometeamID and awayteamID in > the resultset (purely for debugging purposes) then > you should > see the IDs 12 and 13 appearing, but still no team > names under teama or teamb. > > You probably know that you are missing the join > between games and teams. There is no reason why you > cannot have > two joins - "double dipping". Did you try it? > > WHERE...teams.ID=hometeamID AND teams.ID=awayteamID > > NB the above does not imply (as some might at first > think) that hometeamID would have to equal > awayteamID for > this to work, the two ANDs/the two joins are > independently arranged. > > Let us know how you get on! > =dn > > __________________________________________________ Do You Yahoo!? Yahoo! Sports - Coverage of the 2002 Olympic Games http://sports.yahoo.com -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
