PS. You should consider using mysql_fetch_row() or at least mysql_fetch_array() for perforance reasons.
B Bogdan Stancescu wrote: > $query="query"; > $result=mysql_query($query); > $pd=mysql_result($result); > > Notice the zig-zag - $query is first on the left side, then on the > right side, then $result is first on the left side, then on the right > side. > > Bogdan > > Ryan Snow wrote: > >> Hi, Im kinda new to this list. Can anyone tell me what is the proper >> way to interpolate my php variables into my mysql queries? >> >> I've been trying $query = "SELECT password FROM users WHERE >> login='$login'"; >> >> >> then: >> mysql_query($result); >> $pd = mysql_result($result); >> >> but I get a message that says: "Supplied Argument is not a valid >> MySQL-Link resource" >> >> any ideas, anyone? >> > > > > -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
