Try this: SELECT ccsd.Description, ccsd.Impact, ccsd.Isolation FROM ccsd, log WHERE ccsd.logccsd=log.logccsd;
You cannot specify a database is = to a row... Thank you, Ray Hunter Firmware Engineer ENTERASYS NETWORKS -----Original Message----- From: Ron [mailto:[EMAIL PROTECTED]] Sent: Thursday, March 21, 2002 6:32 AM To: [EMAIL PROTECTED] Subject: [PHP-DB] Relational database I am trying to get fields from 2 different tables that have the same field name to pull the records from one table For example mysql_connect($DBhost,$DBuser,$DBpass) or die("Unable toconnect to database"); @mysql_select_db("$DBName") or die("Unable to select database $DBName"); $sqlquery1 = mysql_query("SELECT Description, Impact, Isolation" . "FROM ccsd, log WHERE ccsd=log.logccsd"); while ($query = mysql_fetch_array($sqlquery1)) { $CCSD = $query["CCSD"]; $Description = $query["Description"]; $Impact = $query["Impact"]; $Isolation = $query["Isolation"]; } This code is not working.....help please.........yes I am a newbie! -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
