Hi Barry, Barry Rumsey wrote: > $query_id = mysql_query("INSERT INTO music_album VALUES > (NULL, '$music_artist.id' ,'$album' ,NULL ,NULL)"); > echo " $artist_name and $album has been added to the > > Could someone please point out what I'm doing wrong? >
is the value of $music_artist.id correct? Also, your <select> has the name of "music_artist" and the value of the respective id, isn't that what you want? Regards, Christian -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php