Hi Barry,
Barry Rumsey wrote:
> $query_id = mysql_query("INSERT INTO music_album VALUES
> (NULL, '$music_artist.id' ,'$album' ,NULL ,NULL)");
> echo " $artist_name and $album has been added to the
>
> Could someone please point out what I'm doing wrong?
>
is the value of $music_artist.id correct? Also, your <select> has the
name of "music_artist" and the value of the respective id, isn't that
what you want?
Regards,
Christian
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