Can't you do what you want to do without using two SQL statements? CREATE TABLE IF NOT EXISTS.
Janet ----- Original Message ----- From: "Dave Carrera" <[EMAIL PROTECTED]> To: "php List" <[EMAIL PROTECTED]> Sent: Sunday, May 26, 2002 8:01 AM Subject: [PHP-DB] db sql issue from var Hi All I have found the problem from my last post and need to know how to solve it. Example sql var: $sql =DROP TABLE IF EXISTS test; CREATE TABLE test ......."; When i run the script i get Mysql error near ';' create table...... So how do i run this command from my script to include the ; as part of the sql. phpmyadmin copes with this ok so it must be able to be done. Thanks for any help in advance Dave C -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
