Ok, wrong mailing list!

- Victor > www.argilent.com

-----Original Message-----
From: victor [mailto:[EMAIL PROTECTED]] 
Sent: Monday, September 02, 2002 3:46 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] RE: [PHP] help, array values echoed as Array on loop!

Ok, if I change $ID_arr[] to $ID_arr I think it gives me what I want.

- Victor > www.argilent.com

-----Original Message-----
From: Victor [mailto:[EMAIL PROTECTED]] 
Sent: Monday, September 02, 2002 3:39 PM
To: 'PHP'
Subject: [PHP] help, array values echoed as Array on loop!

I have tried both ways to loop through an array and output the data and
verify that the array is an array and I get no erros but I get this
value, which should not be so.


Here I'm checking if it's an array:

if (!is_array($ID_arr)) { # show error if no array
echo '$ID_arr is not an array.';
}

here I'm counting the keys but it only outputs as 1:

$key = count($ID_arr);
echo $key;

here are two loops that do the same thing and they both output Array:

for($i = 0; $i < count($ID_arr); $i++) {
        echo $ID_arr[$i];
}

foreach($ID_arr as $ind_picture) {
        echo $ind_picture;
}

Why? If it helps, in order to get the array, the values were taken from
a database and exploded from a coma delimited string.

$ID_arr[] = explode(',', $pictures); # make db data into array

This is the string:

15,16,17,18,19

I want each array element to contain 

=> 15 
=> 16
=> 17
etc...

why does it echo as Array?

- Victor > www.argilent.com


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