Hello guys Thanks to all those you helped me with y the question I made before (not a valid MySQL result) it's working now.
Now, I want to display the result of my search with the following code: if($code){ $query_cat = "select author.author_names || ' '|| author.author_surnames as full_name from author, authorxcat where authorxcat.cat_code = $code and author.author_code = authorxcat.author_code" or die($mysql_error()); $result_cat = mysql_query($query_cat); $num_results_cat = mysql_num_rows($result_cat); for ($i=0; $i < $num_results_cat; $i++) { $row = mysql_fetch_array($result); $content .= $row; /* $content .= htmlspecialchars(stripslashes($row["author_names"])) ." ".htmlspecialchars(stripslashes($row ["author_surnames"]))."<br>";*/ } } But I just get the following: ArrayArrayArrayArrayArrayArrayArrayArrayArrayArrayArrayArrayArrayArrayArray I also tried to do it commenting the "$content .= $row;" and uncommenting the lines that are commented in the code but I just get a blank page. What am I doing wrong? Thanks a lot for your help. ******************************************************* Wilmar Pérez Network Administrator Library System Tel: ++57(4)2105145 University of Antioquia Medellín - Colombia 2002 ******************************************************* -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php