Hi,
change line 170 to this:
$form_category_id[$i] = mysql_result($result_category_id, 0, 0);
In each iteration your program executes new SQL query, which
selects only one column from table, and i think, it selects only one row
too. So you have to select first column from first row. With your
code: mysql_result($result_category_id, 0, $i); you try to get value
from first row but from columns 1,2,3,4,5... etc. as for runs through
array.
Hope this helps.
Petr Tomenendal.
On Wed, 2002-10-02 at 18:57, Wilmar Perez wrote:
> Hello guys.
>
> The scenery: I've got an array with some values stored in it. I want to
> retrieve the id code each value is associated to. So I just do the following:
>
> for ($i=0; $i<count($form_category);$i++)
> {
> $query_get_id = "select cat_code from categories
> where cat_name like '$form_category[$i]'";
> $result_category_id = mysql_query($query_get_id) or die(mysql_error());
> $form_category_id[$i] = mysql_result($result_category_id, 0, $i); //This
> is line
> 170
> echo $form_category[$i]." ".$form_category_id[$i]."<br>";
> }
>
> I'm getting the following in my browser (There are some comments I just
> added):
>
> Arquitectura 2 //This is the correct category name and its ID
>
> Warning: Bad column offset specified
> in /var/www/bva/new/common/scripts/admin_functions.php on line 170
> Caricatura //This is the correct category name but the ID is lost
>
> Warning: Bad column offset specified
> in /var/www/bva/new/common/scripts/admin_functions.php on line 170
> Ciencias naturales //Same as before
>
> Any idea of what I'm doing wrong?
>
> *******************************************************
> Wilmar Pérez
> Network Administrator
> Library System
> Tel: ++57(4)2105145
> University of Antioquia
> Medellín - Colombia
> 2002
> *******************************************************
>
>
>
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