Perhaps , $action is not equal to "test". Try initializing the $action
variable - instead of leaving it uninitialized.
<?php
$action = "test";
if($action=="test")
echo "Test";
}
?>
-----Original Message-----
From: Michel Bakkenes - bakkenes.net <[EMAIL PROTECTED]>
To: [EMAIL PROTECTED] <[EMAIL PROTECTED]>
Date: Friday, October 18, 2002 6:26 AM
Subject: [PHP-DB] Variable won't be passed from HTTP address bar
>Ok.. I'm not a newbie I thought.. I do have experience with PHP, but I
>never suffered from this error.
>
>I used on my own redhat 8.0 server the following test-script:
>
>if($action=="test"){ echo "Test";}
>
>I tried it to run with: 127.0.0.1/index.php?action=test
>
>It doesn't print anything. (which means I even can't print hello world
>:P)
>
>Oh, other variable constructions like $bla = "blah" . echo $bla etc. do
>work..
>
>With regards,
>
>Michel Bakkenes
>J2ee developer
>
>Infolook BV
>Zevenbergen, The Netherlands
>
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