Seems to me there should be a built in SQL or PHP command to duplicate a
database. Jeepers. Or to read in a .sql file from PHP and create a
database out of it (which was the original intent).
Anyways, here's a 'hack'. I'd still love to hear anyone else's more
elegant solution.
$V2DB = "V2_SL".$CompanyID;
$result = mysql_create_db($V2DB, $linkI);
if (!$result) $errorstring .= "Error creating ".$V2DB."
database<BR>\n".mysql_errno($linkI).": ".mysql_error($linkI)."<BR>\n";
mysql_select_db ($V2DB, $linkI) or die ("Could not select ".$V2DB."
Database");
/*
//TODO: None of these below here work. Ugh! so frustrating!!
//$filename = "/mypath/todb/V2_DB.sql";
//$fd = fopen ($filename, "r");
//$sql = fread ($fd, filesize ($filename));
//fclose ($fd);
//$lines = file($filename);
//foreach ($lines as $line_num => $line) { $sql .= $line; }
//$sqlTables = explode(";",$sql);
//foreach ($sqlTables as $table)
//{
// echo "<PRE>$table</PRE><p><hr>\n";
// $result = mysql_query($sql,$linkI);
// if (!$result) $errorstring .= "Error creating ".$V2DB."
".$table." table<BR>\n".mysql_errno($linkI).":
".mysql_error($linkI)."<BR>\n";
//}
*/
//You must have already created the "V2_Template" database.
//This will make a clone of it, including data, so most likely leave it
empty
$tableResult = mysql_list_tables ("V2_Template");
while ($row = mysql_fetch_row($tableResult))
{
$tsql = "CREATE TABLE ".$V2DB.".".$row[0]." AS SELECT * FROM
V2_Template.".$row[0];
echo $tsql."<BR>\n";
$tresult = mysql_query($tsql,$linkI);
if (!$tresult) $errorstring .= "Error creating
".$V2DB.".".$row[0]." table<BR>\n".mysql_errno($linkI).":
".mysql_error($linkI)."<BR>\n";
}
> -----Original Message-----
> From: Daevid Vincent [mailto:[EMAIL PROTECTED]]
> Sent: Monday, December 16, 2002 8:00 PM
> To: [EMAIL PROTECTED]
> Subject: [PHP-DB] How can I use PHP to duplicate a mysql
> template database?
>
>
> I need to use PHP to duplicate the schema of a database. This
> seems like
> it should be a simple task -- taking a 'template' db and
> cloning it with
> a new name.
>
> I've tried things like:
>
> $filename = "myDB.sql";
> $fd = fopen ($filename, "r");
> $sql = fread ($fd, filesize ($filename));
> fclose ($fd);
>
> And
>
> $lines = file($filename);
> foreach ($lines as $line_num => $line) { $sql .= $line;
> }
>
> And
> $sql .= "CREATE TABLE IP_Dept (";
> $sql .= " IP_Addr int(10) unsigned NOT NULL default
> '0',";
> $sql .= " DeptID int(10) unsigned NOT NULL default
> '0'";
> $sql .= ");";
>
> $sql .= "CREATE TABLE ResolveTable (";
> $sql .= " IP_Addr int(10) unsigned NOT NULL default
> '0',";
> $sql .= " Name char(255) NOT NULL default '',";
> $sql .= " Custom char(1) default NULL,";
> $sql .= " Global char(1) default 'Y',";
> $sql .= " OSVersion char(255) default NULL,";
> $sql .= " RowID int(10) unsigned NOT NULL
> auto_increment,";
> $sql .= " Display enum('Yes','No') NOT NULL default
> 'Yes',";
> $sql .= " PRIMARY KEY (RowID)";
> $sql .= ");";
>
> echo "<PRE>".$sql."</PRE><P>";
> $result = mysql_query($sql,$linkI);
>
> But ALL of them fail! Ugh!!! Can I not stack commands like that? Is
> there some way to read in a .sql file via PHP? The problem is that my
> web pages are on a web server and the db is on a mysql server
> which are
> different machines, so calling a system() or other execute style
> function won't work for me.
>
> I figured, "Ah! Why don't I just make a template db on the server and
> issue some SQL command to 'clone' that and rename it". You'd
> think that
> was pretty straight forward, but I can't find any examples or commands
> to do this seemingly trivial task. Ideas?
>
>
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