Re: [PHP-DB] Dynamic Variable names

[Ignatius Reilly]

The way to go is:
${"tips_".$i} where $i is your increment control variable

HTH
Ignatius, Brussels

"Where the fuck is Belgium?" (D. Ivester, CEO, Coca-Cola)

----- Original Message -----
From: "David Rice" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Sunday, March 09, 2003 1:34 PM
Subject: [PHP-DB] Dynamic Variable names


>
>
>
>
> Just a quick question about dynamic variables
>
> would like to end up with a variable called
> $tips_1
> $tips_2
> ...
> $tips_n
>
> where "n" is the value of the variable $sid
>
> i have tried
>
> $tips . '$sid';
>
> and other variants, but i can't get one that doesn't return a parse error
or
> T_VARIABLE error.
>
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