Here is basically what I have and what I am getting...
The section of code to copy and then process the copied array:
$other2 = array();
array_push($other2, $other);
foreach ($other2 as $test) {
if ($test == "") {
echo "NOTHING"."<br>";
} else {
echo $test."<br>";
}
}
Basically, what I want is if the array element is nothing, then
output as a test NOTHING. If the array element has some value, then output
as a test that value. Currently, from this code the output I am actually
getting is:
Array
Thanks again.
-----Original Message-----
From: Jonathan Villa [mailto:[EMAIL PROTECTED]
Sent: Wednesday, March 12, 2003 10:58 AM
To: [EMAIL PROTECTED]; NIPP, SCOTT V (SBCSI); 'Hutchins, Richard';
[EMAIL PROTECTED]
Subject: RE: [PHP-DB] Easy array question...
Sorry, I just reread your post
$array_copy = array();
array_push($array_copy, $original_array);
echo $array_copy[0];//or whatever to test
---> Jonathan
-----Original Message-----
From: Jonathan Villa [mailto:[EMAIL PROTECTED]
Sent: Wednesday, March 12, 2003 10:56 AM
To: 'NIPP, SCOTT V (SBCSI)'; 'Hutchins, Richard'; [EMAIL PROTECTED]
Subject: RE: [PHP-DB] Easy array question...
$array_copy = array();
array_push($array_copy, $_SESSION['original_array']);
echo $array_copy[0];//or whatever to test
---> Jonathan
-----Original Message-----
From: NIPP, SCOTT V (SBCSI) [mailto:[EMAIL PROTECTED]
Sent: Wednesday, March 12, 2003 10:43 AM
To: 'Hutchins, Richard'; '[EMAIL PROTECTED]'
Subject: RE: [PHP-DB] Easy array question...
I don't think that is the case because I am able to access the
original array in this same page without having to use the session
variable
reference. Won't hurt to give it a try though. Thanks for the
feedback.
-----Original Message-----
From: Hutchins, Richard [mailto:[EMAIL PROTECTED]
Sent: Wednesday, March 12, 2003 10:40 AM
To: '[EMAIL PROTECTED]'
Subject: RE: [PHP-DB] Easy array question...
Are you using:
$array2 = $_SESSION["array1"];
Not sure that will do the trick, but it was my first inclination.
Rich
> -----Original Message-----
> From: NIPP, SCOTT V (SBCSI) [mailto:[EMAIL PROTECTED]
> Sent: Wednesday, March 12, 2003 11:37 AM
> To: '[EMAIL PROTECTED]'
> Subject: [PHP-DB] Easy array question...
>
>
> I create an array on one page and then process it on
> the next page
> as I have registered the array as a session variable. I need
> to basically
> process one of these arrays twice, so I want to make a copy
> of the array.
> The question is how do I do this? I have tried the following:
>
> $array2 = $array1;
>
> This doesn't seem to do the trick for me. Is this
> correct and I am
> just missing something elsewhere, or is there another way to
> copy an array?
> Thanks.
>
> Scott Nipp
> Phone: (214) 858-1289
> E-mail: [EMAIL PROTECTED]
> Web: http:\\ldsa.sbcld.sbc.com
>
>
>
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