> I am a begginer in PHP programming and I would appreciate any help.
>
> My problem is the following: I need to make the name of my table a
> variable.
> My thought was simple:
>
> $imprimir = mysql_query("SELECT id, data FROM $tabela",$db);
>
> but it doesnt work... how should i do it?
Just like that. Make sure $tabela has a value.
---John W. Holmes...
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