You might be getting an empty result because you don't have anything in $stringarray[1]. You set $i = 0 then have a while loop that does something while $i < 6. But you never go through and increment $i at all so it's always equal to 0. You might get some type of result if you echoed $stringarray[0] in that case.
You should use a for loop and remember to increment ($i++) the variable in the appropriate place inside the for loop. Additionally, I think the proper way to accomplish your array assignment is to state $stringarray = array(). I seem to remember reading somewhere that $stringarray[] = array() isn't quite correct. It works, but it's not correct. It's Friday, it's nice outside and I'm not concentrating much, so I hope this information is of some help. Good luck, Rich > -----Original Message----- > From: Info_Best-IT [mailto:[EMAIL PROTECTED] > Sent: Friday, March 28, 2003 2:13 PM > To: [EMAIL PROTECTED] > Subject: [PHP-DB] Putting a string into a variable. > > > I am having problems putting an html string into a variable > to create an array of > strings. > > something like this: > > > $stringarray[] = array(); > $i = 0; > > while ( $i < 6 ){ > $stringarray[$i] = "<table > cellspacing=\"0\"><tr><td>".$this->differentarray[0] > [0]."</td></tr></table>"; > } > > > When I echo $stringarray[1] it comes up empty... Is there a > special trick to get a > string into an array or even store one as a variable. > > thanks, > /Tim > > -- > PHP Database Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
